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Address and Dereference Operators

Start with Address and Dereference Operators

The address operator & and the dereference operator * are complementary: one produces a pointer and the other accesses its target.

What you’ll learn

  • Explain the main purpose of address and dereference operators.
  • Read and run the complete Go example in this lesson.
  • Apply the concept and recognize common mistakes.

Understand the idea

With value := 12, &value is a *int. Writing *(&value) reads the original integer. Once a pointer is valid, assigning to its dereferenced expression changes the target.

The operator symbols depend on context: *int means a pointer type, *p means dereference, and a * b means multiplication. Go requires an addressable operand for the ordinary address-of operation.

Visualize how it works

Follow this diagram before executing the example. Check where a value or decision changes what runs next.

Visual explanation for address dereferenceAddress and dereference link an expression to the same target.count variableStep 1&count gives *intStep 2*location reads countStep 3*location can updateStep 4Address and dereference link an expression to the same target.
Address and dereference link an expression to the same target.

Run a complete Go example

This example is a complete program. Save it as main.go or paste it into the Go Playground.

Go code

package main

import "fmt"

func main() {
	count := 12
	location := &count
	fmt.Println("Read:", *location)
	*location += 3
	fmt.Println("After change:", count)
	fmt.Println("Addressable value:", *(&count))
}

Output

Read: 12
After change: 15
Addressable value: 15

Trace what the program does

Taking &count produces a pointer to count. Dereferencing it prints 12, and incrementing through that pointer changes count to 15. Dereferencing &count reads the same 15.

Avoid common mistakes

  • The address-of operator does not produce a second copy of the value.
  • The dereference operator requires a valid non-nil pointer.

Try it yourself

Use & and * with a float64 variable, then increase the original value through the pointer.

Tip: Edit the example above, predict the output, and run the modified code to test your reasoning.

Check your understanding

Which expression obtains a pointer to an addressable variable x?
Choose one answer. You can try again.

Answer and explanation

&x

Correct. Taking &count produces a pointer to count.

What you should remember

You have practiced Address and Dereference Operators in a small, self-contained program. The important habit is to predict what runs, inspect the actual output and distinguish the language rule from the particular example.

Before continuing, make sure you can explain the program to someone who has not seen it, including the line that changes its result.

Reaching the recap and completing the quizzes are separate milestones.

    Next lesson: Passing Pointers to Functions →