How to Remove Items from Set based on a Condition in Swift

How to Remove Items from Set based on a Condition in Swift ?

To remove items from a set based on a condition in Swift, you can use the removeAll(where:) method with a closure that defines the condition.

In this example,

We create a set named numberSet containing integer values 1, 2, 3, 4, and 5.
We use the removeAll(where:) method with a closure that checks for even numbers to remove them from the set.
Finally, we print the modified set numberSet to see the removed items.

var numberSet: Set<Int> = [1, 2, 3, 4, 5]
numberSet.removeAll(where: { $0 % 2 == 0 })
print(numberSet)

[1, 3, 5]

In this example,

We create a set named stringSet containing string values "apple", "banana", "cherry", "date", and "grape".
We use the removeAll(where:) method with a closure that checks for string length less than 6 characters to remove them from the set.
Finally, we print the modified set stringSet to see the removed items.

var stringSet: Set<String> = ["apple", "banana", "cherry", "date", "grape"]
stringSet.removeAll(where: { $0.count < 6 })
print(stringSet)

["banana", "cherry"]

In this tutorial, we learned How to Remove Items from Set based on a Condition in Swift language with well detailed examples.