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How to Remove Element from Array based on a Condition in Go

How to Remove Element from Array based on a Condition in Go ?

Answer

In Go, you can use a combination of slice operations and a loop to remove elements from an array based on a condition.


✐ Examples

1 Remove Even Numbers

In this example,

  1. We create a slice named `numbers` with elements including those to be removed based on the condition.
  2. We iterate over the slice using a loop and remove elements that are even.
  3. Finally, we get a new slice with only odd numbers.

Go Program

package main

import (
    "fmt"
)

func main() {
    numbers := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
    oddNumbers := []int{}

    for _, num := range numbers {
        if num % 2 != 0 {
            oddNumbers = append(oddNumbers, num)
        }
    }

    fmt.Println("Slice after filtering:", oddNumbers)
}

Output

Slice after filtering: [1 3 5 7 9]

2 Remove Strings Containing 'a'

In this example,

  1. We create a slice named `words` with elements including those to be removed based on the condition.
  2. We iterate over the slice using a loop and remove strings containing 'a'.
  3. Finally, we get a new slice with strings not containing 'a'.

Go Program

package main

import (
    "fmt"
    "strings"
)

func main() {
    words := []string{"apple", "banana", "grape", "orange", "melon"}
    filteredWords := []string{}

    for _, word := range words {
        if !strings.Contains(word, "a") {
            filteredWords = append(filteredWords, word)
        }
    }

    fmt.Println("Slice after filtering:", filteredWords)
}

Output

Slice after filtering: [melon]

Summary

In this tutorial, we learned How to Remove Element from Array based on a Condition in Go language with well detailed examples.


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