ProgramGuruTo filter elements of an array based on a condition in Go, you can use a loop to iterate through the array and a conditional statement to check each element against the specified condition.
In this example,
filterEvenNumbers that takes an integer slice arr as a parameter.result to store the filtered elements.arr.if statement to check if the current element is even (i.e., num % 2 == 0).result slice.result slice containing only the even numbers.main function, we call the filterEvenNumbers function with a sample array and print the filtered result.package main
import "fmt"
func filterEvenNumbers(arr []int) []int {
result := []int{}
for _, num := range arr {
if num % 2 == 0 {
result = append(result, num)
}
}
return result
}
func main() {
arr := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
evenNumbers := filterEvenNumbers(arr)
fmt.Println("Filtered even numbers:", evenNumbers)
}Filtered even numbers: [2 4 6 8 10]
In this example,
filterStringsContaining that takes a slice of strings arr and a substring substr as parameters.result to store the filtered elements.arr.if statement with the strings.Contains function to check if the current element contains the specified substring.result slice.result slice containing only the strings that include the substring.main function, we call the filterStringsContaining function with a sample array and substring, then print the filtered result.package main
import (
"fmt"
"strings"
)
func filterStringsContaining(arr []string, substr string) []string {
result := []string{}
for _, str := range arr {
if strings.Contains(str, substr) {
result = append(result, str)
}
}
return result
}
func main() {
arr := []string{"apple", "banana", "cherry", "date", "fig", "grape"}
filteredStrings := filterStringsContaining(arr, "a")
fmt.Println("Filtered strings containing 'a':", filteredStrings)
}Filtered strings containing 'a': [apple banana date grape]
In this tutorial, we learned How to Filter Elements of an Array based on a Condition in Go language with well detailed examples.