Rust Tutorials

How to Remove Element from Array based on a Condition in Rust

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How to Remove Element from Array based on a Condition in Rust ?

Answer

In Rust, you can use iterators and filter methods to remove elements based on a condition.

✐ Examples

1 Remove Odd Numbers

In this example,

We create a vector `numbers` with elements including those to be removed based on the condition.
We use the `filter` method with a closure to create an iterator excluding odd numbers.
We collect the filtered iterator into a new vector.

Rust Program

fn main() {
    let numbers = vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
    let filtered_numbers: Vec<i32> = numbers.into_iter().filter(|&num| num % 2 == 0).collect();

    println!("Vector after filtering: {:?}", filtered_numbers);
}

Output

Vector after filtering: [2, 4, 6, 8, 10]

2 Remove Strings Containing 'a'

In this example,

We create a vector `words` with elements including those to be removed based on the condition.
We use the `filter` method with a closure to create an iterator excluding strings containing 'a'.
We collect the filtered iterator into a new vector.

Rust Program

fn main() {
    let words = vec!["apple", "banana", "grape", "orange", "melon"];
    let filtered_words: Vec<&str> = words.into_iter().filter(|&word| !word.contains('a')).collect();

    println!("Vector after filtering: {:?}", filtered_words);
}

Output

Vector after filtering: ["grape"]

Summary

In this tutorial, we learned How to Remove Element from Array based on a Condition in Rust language with well detailed examples.

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How to Remove Element from Array based on a Condition in Rust

How to Remove Element from Array based on a Condition in Rust ?

Answer

✐ Examples

1 Remove Odd Numbers

Rust Program

Output

2 Remove Strings Containing 'a'

Rust Program

Output

Summary

More Rust Arrays Tutorials