In this tutorial, we will learn how to find the sum of the first N natural numbers using recursion in Python. We will cover the basic concept of recursion and implement a recursive function to calculate the sum.

The sum of the first N natural numbers is the sum of all positive integers from 1 to N. This can be calculated recursively by adding the current number to the sum of the previous numbers.

The syntax to find the sum of the first N natural numbers using recursion in Python is:

```
def sum_of_natural_numbers(n):
if n == 1:
return 1
else:
return n + sum_of_natural_numbers(n - 1)
```

We can create a recursive function to calculate the sum of the first N natural numbers.

For example,

- Define a function named
`sum_of_natural_numbers`

that takes one parameter`n`

. - Check if
`n`

is equal to 1. If true, return 1 (base case). - Otherwise, return
`n`

plus the result of calling`sum_of_natural_numbers`

with`n - 1`

(recursive case). - Call the function with a sample value and print the result.

```
def sum_of_natural_numbers(n):
if n == 1:
return 1
else:
return n + sum_of_natural_numbers(n - 1)
# Find the sum of the first 10 natural numbers
result = sum_of_natural_numbers(10)
# Print the result
print('Sum of the first 10 natural numbers is', result)
```

Sum of the first 10 natural numbers is 55