C Program to Multiply Two Matrices
C Program to Multiply Two Matrices
A small school table has two rows and two columns. The matrix multiplication operation should preserve what each row and column means, rather than treating the table as four unrelated values.
Matrix multiplication computes each result entry as a row-column dot product, not as an entrywise product.
Before this exercise, review array indexes and bounds and nested loops. The worked program below applies those ideas to this specific problem.
Explain
Explain why matrix multiplication uses this sequence of operations.
Trace
Trace the sample values and predict the printed result.
Apply
Multiply the original matrix by the two-by-two identity matrix.
Matrix Multiplication: follow the data
Given data
A small school table has two rows and two columns. The matrix multiplication operation should preserve what each row and column means, rather than treating the table as four unrelated values.
Rule
Matrix multiplication computes each result entry as a row-column dot product, not as an entrywise product.
Observed result
19 22 43 50
Understand the operation
For every output position, multiply pairs along the left row and right column, then add those products. The shared inner dimension supplies the loop over k.
The example fixes both dimensions at two so every index can be checked directly. A general matrix interface must carry dimensions, require compatible shapes for its operation and validate storage for each referenced element.
Read the complete C program
The input values are written into this complete C17 example so the calculation can be reproduced without an unavailable service. Change the named data, rebuild and compare the actual output with your prediction.
C17 · complete program
#include <stdio.h>
int main(void) {
int matrix[2][2] = {{1, 2}, {3, 4}};
int other[2][2] = {{5, 6}, {7, 8}}, result[2][2] = {{0}};
for (int row = 0; row < 2; row++) for (int col = 0; col < 2; col++) for (int k = 0; k < 2; k++) result[row][col] += matrix[row][k] * other[k][col];
for (int row = 0; row < 2; row++) { for (int col = 0; col < 2; col++) printf("%d%s", result[row][col], col == 1 ? "\n" : " "); }
return 0;
}
Expected output
19 22
43 50
Run in C compiler →Follow the values through the code
C17 · code used in this explanation
#include <stdio.h>
int main(void) {
int matrix[2][2] = {{1, 2}, {3, 4}};
int other[2][2] = {{5, 6}, {7, 8}}, result[2][2] = {{0}};
for (int row = 0; row < 2; row++) for (int col = 0; col < 2; col++) for (int k = 0; k < 2; k++) result[row][col] += matrix[row][k] * other[k][col];
for (int row = 0; row < 2; row++) { for (int col = 0; col < 2; col++) printf("%d%s", result[row][col], col == 1 ? "\n" : " "); }
return 0;
}
Result (0,0) is 1×5 + 2×7 = 19. Result (0,1) is 1×6 + 2×8 = 22.
Read the resulting rows in order; moving a value to another row or column is part of the operation’s meaning, not merely an output-format choice.
Follow the worked calculation
Start with the sample
Result (0,0) is 1×5 + 2×7 = 19. Result (0,1) is 1×6 + 2×8 = 22.
Apply the rule
Read the resulting rows in order; moving a value to another row or column is part of the operation’s meaning, not merely an output-format choice.
Check the result
19 22 43 50
19 22 43 50
Try a small variation
C17 · code used in this explanation
#include <stdio.h>
int main(void) {
int matrix[2][2] = {{1, 2}, {3, 4}};
int other[2][2] = {{5, 6}, {7, 8}}, result[2][2] = {{0}};
for (int row = 0; row < 2; row++) for (int col = 0; col < 2; col++) for (int k = 0; k < 2; k++) result[row][col] += matrix[row][k] * other[k][col];
for (int row = 0; row < 2; row++) { for (int col = 0; col < 2; col++) printf("%d%s", result[row][col], col == 1 ? "\n" : " "); }
return 0;
}
Multiply the original matrix by the two-by-two identity matrix.
Worked answer
The complete worked answer uses the same valid two-by-two input. Trace its index rule independently; compare each printed result with the source element or accumulation that produced it.
C17 · complete program
#include <stdio.h>
int main(void) {
int matrix[2][2] = {{1, 2}, {3, 4}};
int other[2][2] = {{1, 0}, {0, 1}}, result[2][2] = {{0}};
for (int row = 0; row < 2; row++) for (int col = 0; col < 2; col++) for (int k = 0; k < 2; k++) result[row][col] += matrix[row][k] * other[k][col];
for (int row = 0; row < 2; row++) { for (int col = 0; col < 2; col++) printf("%d%s", result[row][col], col == 1 ? "\n" : " "); }
return 0;
}
Expected output
1 2
3 4
Run in C compiler →Recognize the important boundaries
The left column count must equal the right row count. Multiplication is not generally commutative, even when both orders are dimensionally valid.
Larger or untrusted dimensions require checked storage-size calculations. Integer products and accumulated sums also need a representable-range contract.
Check your understanding
Choose the answer, then compare the reasoning for every option.
Check your understanding
Choose the answer, then compare the reasoning for every option.
Use the idea independently
Matrix multiplication computes each result entry as a row-column dot product, not as an entrywise product.
Continue with array boundaries.
Continue with function bounds contracts.
Language reference: WG14 C11 committee draft. These examples use the C17-compatible subset of the explained language features.
Reaching the recap and completing the quizzes are separate milestones.