How to Remove Element from List based on a Condition in Kotlin


How to Remove Element from List based on a Condition in Kotlin ?

Answer

To remove elements from a list based on a condition in Kotlin, you can use the `removeIf` method.



✐ Examples

1 Remove Elements Greater Than a Threshold

In this example,

  1. We create a mutable list named numbers with some elements.
  2. We specify the threshold value.
  3. We use the removeIf method of the list along with a lambda function to remove elements greater than the threshold.
  4. Finally, we print the modified list to standard output.

Kotlin Program

fun main() {
    val numbers = mutableListOf(1, 2, 3, 4, 5)
    val threshold = 3
    numbers.removeIf { it > threshold }
    println("Modified list after removing elements greater than $threshold: $numbers")
}

Output

Modified list after removing elements greater than 3: [1, 2, 3]

2 Remove Elements Matching a Predicate

In this example,

  1. We create a mutable list named names with some elements.
  2. We define a predicate function isLongName that returns true if the length of the string is greater than a specified value.
  3. We use the removeIf method of the list along with the isLongName predicate to remove elements matching the predicate condition.
  4. Finally, we print the modified list to standard output.

Kotlin Program

fun main() {
    val names = mutableListOf("John", "Alice", "Michael", "Emma")
    val maxLength = 5
    val isLongName: (String) -> Boolean = { it.length > maxLength }
    names.removeIf(isLongName)
    println("Modified list after removing long names: $names")
}

Output

Modified list after removing long names: [John, Alice, Emma]

Summary

In this tutorial, we learned How to Remove Element from List based on a Condition in Kotlin language with well detailed examples.




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