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ArrayList removeAll() method - Syntax and Examples

ArrayList removeAll() method - Syntax and Examples

Learn how to use the Java ArrayList `removeAll()` method to remove all elements that are also present in a specified collection. Includes syntax, parameters, return values, and practical examples.

This reference explains ArrayList removeAll() method - Syntax and Examples through its syntax, examples and boundaries. Use the linked course lessons when the surrounding Java concepts are unfamiliar.

  1. Use this reference

    Identify the documented behavior, read a complete example and check its inputs before applying it.

ArrayList removeAll() method - Syntax and Examples

Introduction

Sometimes you need to remove a group of elements from an ArrayList at once. The removeAll() method is your friend for that! It allows you to specify another Collection (like another ArrayList, a HashSet, etc.) and removes all elements present in *that* collection from the original ArrayList.

Syntax

public boolean removeAll(Collection c)

Parameters

Parameter Description
c The collection containing elements to be removed from this ArrayList. The removeAll() method will remove all occurrences of the elements present in `c` from the current list.

Return Value

The removeAll() method returns a boolean value: true if the ArrayList was modified (meaning at least one element was removed), and false otherwise.

Examples

Example 1: Removing Elements from Another ArrayList

This example demonstrates removing elements present in another ArrayList. We'll start with two lists, remove the common elements from the first list, and then observe the result.

import java.util.ArrayList;  // Import ArrayList class
import java.util.Arrays;

public class RemoveAllExample1 {

    public static void main(String[] args) {

        // Create two ArrayLists
        ArrayList list1 = new ArrayList<>(Arrays.asList("apple", "banana", "cherry", "date", "fig"));
        ArrayList list2 = new ArrayList<>(Arrays.asList("banana", "date", "grape"));

        System.out.println("Original List 1: " + list1);
        System.out.println("List 2 (elements to remove): " + list2);

        // Remove all elements from list1 that are also in list2
        boolean removed = list1.removeAll(list2);

        System.out.println("List 1 after removal: " + list1);
        System.out.println("Was the list modified? " + removed);
    }
}
Original List 1: [apple, banana, cherry, date, fig]
List 2 (elements to remove): [banana, date, grape]
List 1 after removal: [apple, cherry, fig]
Was the list modified? true

Explanation: We created two lists. The `removeAll()` method was called on list1 using list2 as the collection of elements to remove. Elements “banana” and “date”, which are present in both lists, were removed from list1. Because list1 changed (elements were removed), `removed` is true.

Example 2: Removing Elements Using a HashSet

This example shows how to use a HashSet as the collection for removal. The primary difference here isn't functionality but demonstrates that any Collection can be passed to `removeAll()`

import java.util.ArrayList; // Import ArrayList class
import java.util.Arrays; 
import java.util.HashSet;  // Import HashSet class

public class RemoveAllExample2 {

    public static void main(String[] args) {

        // Create an ArrayList
        ArrayList list = new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5));

        // Create a HashSet containing elements to remove
        HashSet setToRemove = new HashSet<>(Arrays.asList(2, 4));

        System.out.println("Original List: " + list);
        System.out.println("Set of elements to remove: " + setToRemove);

        // Remove all elements from the ArrayList that are also in the HashSet
        boolean removed = list.removeAll(setToRemove);

        System.out.println("List after removal: " + list);
        System.out.println("Was the list modified? " + removed);
    }
}
Original List: [1, 2, 3, 4, 5]
Set of elements to remove: [2, 4]
List after removal: [1, 3, 5]
Was the list modified? true

Explanation: We created an ArrayList and a HashSet. The removeAll() method removed all elements present in the HashSet from the ArrayList, resulting in “2” and “4” being removed.

Example 3: No Common Elements

This example illustrates what happens when there are no common elements between the two collections. The list remains unchanged, and `removeAll()` returns false.

import java.util.ArrayList; // Import ArrayList class
import java.util.Arrays; 

public class RemoveAllExample3 {

    public static void main(String[] args) {

        // Create two ArrayLists with no common elements
        ArrayList list1 = new ArrayList<>(Arrays.asList("apple", "banana", "cherry"));
        ArrayList list2 = new ArrayList<>(Arrays.asList("grape", "kiwi", "mango"));

        System.out.println("Original List 1: " + list1);
        System.out.println("List 2 (elements to remove): " + list2);

        // Remove all elements from list1 that are also in list2
        boolean removed = list1.removeAll(list2);

        System.out.println("List 1 after removal: " + list1);
        System.out.println("Was the list modified? " + removed);
    }
}
Original List 1: [apple, banana, cherry]
List 2 (elements to remove): [grape, kiwi, mango]
List 1 after removal: [apple, banana, cherry]
Was the list modified? false

Explanation: Because there are no common elements between list1 and list2, nothing is removed. The original list remains unchanged, so the returned boolean value is false.

Using this reference

Check the example’s types, inputs and documented behavior before copying it into an application. Some APIs require external libraries, files or platform services; consult their setup notes.

Related explanations: Java Data Types - Primitive and Non-Primitive, Java Class - Blueprint of Objects, Exceptions in Java Introduction.

Supporting documentation: Official Java learning guide.

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