Yandex

Binary TreesBinary Trees36

  1. 1Preorder Traversal of a Binary Tree using Recursion
  2. 2Preorder Traversal of a Binary Tree using Iteration
  3. 3Postorder Traversal of a Binary Tree Using Recursion
  4. 4Postorder Traversal of a Binary Tree using Iteration
  5. 5Level Order Traversal of a Binary Tree using Recursion
  6. 6Level Order Traversal of a Binary Tree using Iteration
  7. 7Reverse Level Order Traversal of a Binary Tree using Iteration
  8. 8Reverse Level Order Traversal of a Binary Tree using Recursion
  9. 9Find Height of a Binary Tree
  10. 10Find Diameter of a Binary Tree
  11. 11Find Mirror of a Binary Tree - Todo
  12. 12Inorder Traversal of a Binary Tree using Recursion
  13. 13Inorder Traversal of a Binary Tree using Iteration
  14. 14Left View of a Binary Tree
  15. 15Right View of a Binary Tree
  16. 16Top View of a Binary Tree
  17. 17Bottom View of a Binary Tree
  18. 18Zigzag Traversal of a Binary Tree
  19. 19Check if a Binary Tree is Balanced
  20. 20Diagonal Traversal of a Binary Tree
  21. 21Boundary Traversal of a Binary Tree
  22. 22Construct a Binary Tree from a String with Bracket Representation
  23. 23Convert a Binary Tree into a Doubly Linked List
  24. 24Convert a Binary Tree into a Sum Tree
  25. 25Find Minimum Swaps Required to Convert a Binary Tree into a BST
  26. 26Check if a Binary Tree is a Sum Tree
  27. 27Check if All Leaf Nodes are at the Same Level in a Binary Tree
  28. 28Lowest Common Ancestor (LCA) in a Binary Tree
  29. 29Solve the Tree Isomorphism Problem
  30. 30Check if a Binary Tree Contains Duplicate Subtrees of Size 2 or More
  31. 31Check if Two Binary Trees are Mirror Images
  32. 32Calculate the Sum of Nodes on the Longest Path from Root to Leaf in a Binary Tree
  33. 33Print All Paths in a Binary Tree with a Given Sum
  34. 34Find the Distance Between Two Nodes in a Binary Tree
  35. 35Find the kth Ancestor of a Node in a Binary Tree
  36. 36Find All Duplicate Subtrees in a Binary Tree

GraphsGraphs46

  1. 1Breadth-First Search in Graphs
  2. 2Depth-First Search in Graphs
  3. 3Number of Provinces in an Undirected Graph
  4. 4Connected Components in a Matrix
  5. 5Rotten Oranges Problem - BFS in Matrix
  6. 6Flood Fill Algorithm - Graph Based
  7. 7Detect Cycle in an Undirected Graph using DFS
  8. 8Detect Cycle in an Undirected Graph using BFS
  9. 9Distance of Nearest Cell Having 1 - Grid BFS
  10. 10Surrounded Regions in Matrix using Graph Traversal
  11. 11Number of Enclaves in Grid
  12. 12Word Ladder - Shortest Transformation using Graph
  13. 13Word Ladder II - All Shortest Transformation Sequences
  14. 14Number of Distinct Islands using DFS
  15. 15Check if a Graph is Bipartite using DFS
  16. 16Topological Sort Using DFS
  17. 17Topological Sort using Kahn's Algorithm
  18. 18Cycle Detection in Directed Graph using BFS
  19. 19Course Schedule - Task Ordering with Prerequisites
  20. 20Course Schedule 2 - Task Ordering Using Topological Sort
  21. 21Find Eventual Safe States in a Directed Graph
  22. 22Alien Dictionary Character Order
  23. 23Shortest Path in Undirected Graph with Unit Distance
  24. 24Shortest Path in DAG using Topological Sort
  25. 25Dijkstra's Algorithm Using Set - Shortest Path in Graph
  26. 26Dijkstra’s Algorithm Using Priority Queue
  27. 27Shortest Distance in a Binary Maze using BFS
  28. 28Path With Minimum Effort in Grid using Graphs
  29. 29Cheapest Flights Within K Stops - Graph Problem
  30. 30Number of Ways to Reach Destination in Shortest Time - Graph Problem
  31. 31Minimum Multiplications to Reach End - Graph BFS
  32. 32Bellman-Ford Algorithm for Shortest Paths
  33. 33Floyd Warshall Algorithm for All-Pairs Shortest Path
  34. 34Find the City With the Fewest Reachable Neighbours
  35. 35Minimum Spanning Tree in Graphs
  36. 36Prim's Algorithm for Minimum Spanning Tree
  37. 37Disjoint Set (Union-Find) with Union by Rank and Path Compression
  38. 38Kruskal's Algorithm - Minimum Spanning Tree
  39. 39Minimum Operations to Make Network Connected
  40. 40Most Stones Removed with Same Row or Column
  41. 41Accounts Merge Problem using Disjoint Set Union
  42. 42Number of Islands II - Online Queries using DSU
  43. 43Making a Large Island Using DSU
  44. 44Bridges in Graph using Tarjan's Algorithm
  45. 45Articulation Points in Graphs
  46. 46Strongly Connected Components using Kosaraju's Algorithm

TriesTries1

Topological Sort
Using Kahn's Algorithm (BFS)



Problem Statement

Topological Sort of a directed graph is a linear ordering of its vertices such that for every directed edge u → v, vertex u comes before v in the ordering.

Kahn’s Algorithm uses a BFS-based approach and is suitable for Directed Acyclic Graphs (DAGs). It efficiently produces a valid topological ordering or detects the presence of a cycle.

Examples

Graph (Edges) Topological Order Description
[[5, 2], [5, 0], [4, 0], [4, 1], [2, 3], [3, 1]] [4, 5, 2, 3, 1, 0] Valid topological sort respecting all dependencies
[[0, 1], [1, 2], [2, 3]] [0, 1, 2, 3] Simple linear DAG
[] [] Empty graph has no vertices to sort
[[0, 1], [1, 0]] null Graph contains a cycle, so topological sort is not possible
[[1, 3], [2, 3], [3, 4]] [1, 2, 3, 4] Multiple valid orderings possible

Solution

Understanding the Problem

Topological sorting of a directed graph is a linear ordering of its vertices such that for every directed edge u → v, vertex u comes before v in the ordering. This is only possible if the graph has no cycles, i.e., it is a Directed Acyclic Graph (DAG).

Step-by-Step Explanation

We use Kahn's Algorithm, which is a breadth-first search (BFS) based approach. First, we calculate the indegree (number of incoming edges) for each vertex. Then we enqueue all vertices that have an indegree of 0, as these have no prerequisites and can safely be placed at the beginning of the ordering.

We then process the queue:

  • Remove a node u from the front of the queue and add it to the result list.
  • For each neighbor v of u, decrease its indegree by 1 because the edge u → v has now been 'used'.
  • If v's indegree becomes 0, it means all its prerequisites have been processed, and we enqueue v.

Cycle Detection

If, at the end, our result list does not contain all the vertices, it means there is a cycle in the graph. The cycle prevents some nodes from ever reaching an indegree of 0, thus making topological sort impossible. In that case, we return null.

Different Cases

Case 1: Normal DAG

Suppose we have a graph with a clear hierarchy of dependencies (like a build system). Kahn’s algorithm will give us one of the valid topological orderings that obey all constraints.

Case 2: Multiple Valid Orders

When more than one node has an indegree of 0 at the same time, the order of their insertion into the queue can vary, leading to multiple valid topological sorts.

Case 3: Graph with a Cycle

If there’s a cycle (like 1 → 2 → 3 → 1), no node in the cycle will ever reach an indegree of 0 after initialization. The queue becomes empty before we process all nodes. Thus, the result list will not include all vertices, and we detect the cycle.

Algorithm Steps

  1. Compute the indegree of each vertex.
  2. Initialize a queue and enqueue all vertices with indegree 0.
  3. Initialize an empty list to store the topological order.
  4. While the queue is not empty:
    1. Dequeue a vertex u and add it to the result list.
    2. For each neighbor v of u:
      1. Decrease indegree[v] by 1.
      2. If indegree[v] == 0, enqueue v.
  5. If the result contains all vertices, return the result.
  6. Else, return null (cycle detected).

Code

JavaScript
function topologicalSortKahn(V, edges) {
  const indegree = Array(V).fill(0);
  const graph = Array.from({ length: V }, () => []);
  const result = [];

  for (const [u, v] of edges) {
    graph[u].push(v);
    indegree[v]++;
  }

  const queue = [];
  for (let i = 0; i < V; i++) {
    if (indegree[i] === 0) queue.push(i);
  }

  while (queue.length) {
    const node = queue.shift();
    result.push(node);
    for (const neighbor of graph[node]) {
      indegree[neighbor]--;
      if (indegree[neighbor] === 0) queue.push(neighbor);
    }
  }

  return result.length === V ? result : null;
}

const V = 6;
const edges = [[5, 2], [5, 0], [4, 0], [4, 1], [2, 3], [3, 1]];
console.log("Topological Sort:", topologicalSortKahn(V, edges));

Time Complexity

CaseTime ComplexityExplanation
Best CaseO(V + E)Even in the best case, we must visit all vertices and all edges once to compute indegrees and process the graph structure.
Average CaseO(V + E)For any valid DAG, each vertex and edge is processed exactly once.
Worst CaseO(V + E)Regardless of graph structure (as long as it is a DAG), we always have to check every node and every edge at least once.

Space Complexity

O(V + E)

Explanation: We use additional space for the adjacency list (O(E)), indegree array (O(V)), the queue (O(V)), and result list (O(V)).



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