Binary TreesBinary Trees36

  1. 1Preorder Traversal of a Binary Tree using Recursion
  2. 2Preorder Traversal of a Binary Tree using Iteration
  3. 3Postorder Traversal of a Binary Tree Using Recursion
  4. 4Postorder Traversal of a Binary Tree using Iteration
  5. 5Level Order Traversal of a Binary Tree using Recursion
  6. 6Level Order Traversal of a Binary Tree using Iteration
  7. 7Reverse Level Order Traversal of a Binary Tree using Iteration
  8. 8Reverse Level Order Traversal of a Binary Tree using Recursion
  9. 9Find Height of a Binary Tree
  10. 10Find Diameter of a Binary Tree
  11. 11Find Mirror of a Binary Tree - Todo
  12. 12Inorder Traversal of a Binary Tree using Recursion
  13. 13Inorder Traversal of a Binary Tree using Iteration
  14. 14Left View of a Binary Tree
  15. 15Right View of a Binary Tree
  16. 16Top View of a Binary Tree
  17. 17Bottom View of a Binary Tree
  18. 18Zigzag Traversal of a Binary Tree
  19. 19Check if a Binary Tree is Balanced
  20. 20Diagonal Traversal of a Binary Tree
  21. 21Boundary Traversal of a Binary Tree
  22. 22Construct a Binary Tree from a String with Bracket Representation
  23. 23Convert a Binary Tree into a Doubly Linked List
  24. 24Convert a Binary Tree into a Sum Tree
  25. 25Find Minimum Swaps Required to Convert a Binary Tree into a BST
  26. 26Check if a Binary Tree is a Sum Tree
  27. 27Check if All Leaf Nodes are at the Same Level in a Binary Tree
  28. 28Lowest Common Ancestor (LCA) in a Binary Tree
  29. 29Solve the Tree Isomorphism Problem
  30. 30Check if a Binary Tree Contains Duplicate Subtrees of Size 2 or More
  31. 31Check if Two Binary Trees are Mirror Images
  32. 32Calculate the Sum of Nodes on the Longest Path from Root to Leaf in a Binary Tree
  33. 33Print All Paths in a Binary Tree with a Given Sum
  34. 34Find the Distance Between Two Nodes in a Binary Tree
  35. 35Find the kth Ancestor of a Node in a Binary Tree
  36. 36Find All Duplicate Subtrees in a Binary Tree

Rotate a Matrix by 90 Degrees Clockwise
Optimal In-place Algorithm



Problem Statement

Given a square matrix of size n x n, rotate the entire matrix by 90 degrees in the clockwise direction. The rotation should be done in-place, meaning no extra matrix should be used for the transformation.

Examples

Input MatrixOutput MatrixDescription
[[1,2],[3,4]][[3,1],[4,2]]2x2 matrix rotated 90° clockwise
[[1,2,3],[4,5,6],[7,8,9]][[7,4,1],[8,5,2],[9,6,3]]Standard 3x3 matrix rotation
[[1]][[1]]Single element matrix remains unchanged
[][]Empty matrix has no elements to rotate
[[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]][[13,9,5,1],[14,10,6,2],[15,11,7,3],[16,12,8,4]]4x4 matrix rotated in-place

Solution

To rotate a square matrix by 90 degrees clockwise without using extra space, we need to reposition the elements in-place. Instead of rotating each layer individually (which is another method), this optimal approach uses two simple steps:

Step 1: Transpose the Matrix

Transposing a matrix means converting rows into columns. We swap every element matrix[i][j] with matrix[j][i] for all i < j. After this step, the matrix is flipped along its diagonal.

Step 2: Reverse Each Row

Now, we reverse each row in the transposed matrix. This aligns all the elements to their new 90-degree rotated positions.

Why This Works

When we transpose the matrix, the top row becomes the left column. But to fully rotate it clockwise, we still need to move the last column to the top, which is achieved by reversing each row after transposition.

Let’s Discuss Different Scenarios

  • Normal Square Matrix: For matrices like 2x2, 3x3, or 4x4, the algorithm works seamlessly and efficiently, with no extra space used.
  • Matrix with One Element: Rotating a 1x1 matrix has no visible effect. The matrix stays the same.
  • Empty Matrix: There's nothing to rotate. The function should simply return an empty list or matrix.
  • Non-Square Matrix: This approach only works on square matrices (equal number of rows and columns). If the matrix is not square, this logic should not be applied as it would produce incorrect results.

Because we don’t use any extra space, this is an in-place O(1) space and O(n²) time solution, where n is the number of rows (or columns).

Visualization

Algorithm Steps

  1. Given an n x n square matrix.
  2. Step 1: Transpose the matrix: swap matrix[i][j] with matrix[j][i] for all i < j.
  3. Step 2: Reverse each row of the matrix.
  4. The matrix is now rotated 90 degrees clockwise.

Code

Python
JavaScript
Java
C++
C
def rotate_matrix(matrix):
    n = len(matrix)
    # Transpose the matrix
    for i in range(n):
        for j in range(i + 1, n):
            matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]

    # Reverse each row
    for row in matrix:
        row.reverse()

    return matrix

# Sample Input
mat = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9]
]
rotated = rotate_matrix(mat)
for row in rotated:
    print(row)


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