Binary TreesBinary Trees36

  1. 1Preorder Traversal of a Binary Tree using Recursion
  2. 2Preorder Traversal of a Binary Tree using Iteration
  3. 3Postorder Traversal of a Binary Tree Using Recursion
  4. 4Postorder Traversal of a Binary Tree using Iteration
  5. 5Level Order Traversal of a Binary Tree using Recursion
  6. 6Level Order Traversal of a Binary Tree using Iteration
  7. 7Reverse Level Order Traversal of a Binary Tree using Iteration
  8. 8Reverse Level Order Traversal of a Binary Tree using Recursion
  9. 9Find Height of a Binary Tree
  10. 10Find Diameter of a Binary Tree
  11. 11Find Mirror of a Binary Tree - Todo
  12. 12Inorder Traversal of a Binary Tree using Recursion
  13. 13Inorder Traversal of a Binary Tree using Iteration
  14. 14Left View of a Binary Tree
  15. 15Right View of a Binary Tree
  16. 16Top View of a Binary Tree
  17. 17Bottom View of a Binary Tree
  18. 18Zigzag Traversal of a Binary Tree
  19. 19Check if a Binary Tree is Balanced
  20. 20Diagonal Traversal of a Binary Tree
  21. 21Boundary Traversal of a Binary Tree
  22. 22Construct a Binary Tree from a String with Bracket Representation
  23. 23Convert a Binary Tree into a Doubly Linked List
  24. 24Convert a Binary Tree into a Sum Tree
  25. 25Find Minimum Swaps Required to Convert a Binary Tree into a BST
  26. 26Check if a Binary Tree is a Sum Tree
  27. 27Check if All Leaf Nodes are at the Same Level in a Binary Tree
  28. 28Lowest Common Ancestor (LCA) in a Binary Tree
  29. 29Solve the Tree Isomorphism Problem
  30. 30Check if a Binary Tree Contains Duplicate Subtrees of Size 2 or More
  31. 31Check if Two Binary Trees are Mirror Images
  32. 32Calculate the Sum of Nodes on the Longest Path from Root to Leaf in a Binary Tree
  33. 33Print All Paths in a Binary Tree with a Given Sum
  34. 34Find the Distance Between Two Nodes in a Binary Tree
  35. 35Find the kth Ancestor of a Node in a Binary Tree
  36. 36Find All Duplicate Subtrees in a Binary Tree

Roman Number to Integer



Problem Statement

Given a Roman numeral string, your task is to convert it into its corresponding integer value.

Roman numerals are represented by combinations of the following characters:

Some combinations follow a subtractive pattern, such as:

Your job is to correctly interpret these symbols and return the total integer value. The input string is guaranteed to be a valid Roman numeral or an empty string.

Examples

Input (Roman)Output (Integer)Description
III3Simple addition: 1 + 1 + 1 = 3
IV4Subtractive case: 5 - 1 = 4
IX9Subtractive case: 10 - 1 = 9
LVIII5850 + 5 + 1 + 1 + 1 = 58
MCMXCIV19941000 + (1000 - 100) + (100 - 10) + (5 - 1) = 1994
X10Single symbol: 10
0Empty string returns 0

Solution

To convert a Roman numeral to an integer, we need to carefully process the characters from left to right.

Understanding Roman Numerals

Each Roman character represents a fixed value. For example, I = 1, V = 5, X = 10, etc. Normally, you just add these values together. So VIII = 5 + 1 + 1 + 1 = 8.

But Wait – Some Subtractive Cases

Sometimes a smaller value appears before a larger one, which means we subtract instead of add. For example:

  • IV = 4 (5 - 1)
  • IX = 9 (10 - 1)
  • XL = 40 (50 - 10)

So, while scanning from left to right, if the current character has a value less than the next, we subtract it. Otherwise, we add it.

How This Works in Practice

Let’s take MCMXCIV as an example:

  • M = 1000 (add)
  • CM = 900 (100 before 1000 → subtract 100)
  • XC = 90 (10 before 100 → subtract 10)
  • IV = 4 (1 before 5 → subtract 1)

Total: 1000 + 900 + 90 + 4 = 1994

What Happens with an Empty String?

If the input is empty, we simply return 0. There’s nothing to convert.

Conclusion

This approach is both simple and efficient. By carefully comparing each character with the next one, we can accurately compute the total integer value. It works in O(n) time where n is the length of the Roman numeral.

Algorithm Steps

  1. Create a map of Roman characters to their integer values.
  2. Initialize result = 0.
  3. Iterate over the string from left to right:
  4. → If current value is less than next value, subtract it.
  5. → Else, add it.
  6. Return the final result.

Code

Python
Java
JavaScript
C
C++
C#
Kotlin
Swift
Go
Php
def roman_to_int(s):
    roman_map = {'I': 1, 'V': 5, 'X': 10, 'L': 50,
                 'C': 100, 'D': 500, 'M': 1000}
    total = 0
    prev = 0

    for ch in reversed(s):
        curr = roman_map[ch]
        if curr < prev:
            total -= curr  # Subtract if smaller numeral before larger one
        else:
            total += curr  # Add otherwise
        prev = curr

    return total

# Example
print(roman_to_int("MCMXCIV"))  # Output: 1994

Time Complexity

CaseTime ComplexityExplanation
Best CaseO(n)The algorithm goes through the Roman numeral string once, where n is its length.
Average CaseO(n)In all scenarios, every character is processed once.
Average CaseO(n)No matter the combination, we always loop through all characters.

Space Complexity

O(1)

Explanation: Only constant space is used to store the result and the mapping of characters.



Welcome to ProgramGuru

Sign up to start your journey with us

Support ProgramGuru.org

You can support this website with a contribution of your choice.

When making a contribution, mention your name, and programguru.org in the message. Your name shall be displayed in the sponsors list.

PayPal

UPI

PhonePe QR

MALLIKARJUNA M