Yandex

Binary TreesBinary Trees36

  1. 1Preorder Traversal of a Binary Tree using Recursion
  2. 2Preorder Traversal of a Binary Tree using Iteration
  3. 3Postorder Traversal of a Binary Tree Using Recursion
  4. 4Postorder Traversal of a Binary Tree using Iteration
  5. 5Level Order Traversal of a Binary Tree using Recursion
  6. 6Level Order Traversal of a Binary Tree using Iteration
  7. 7Reverse Level Order Traversal of a Binary Tree using Iteration
  8. 8Reverse Level Order Traversal of a Binary Tree using Recursion
  9. 9Find Height of a Binary Tree
  10. 10Find Diameter of a Binary Tree
  11. 11Find Mirror of a Binary Tree - Todo
  12. 12Inorder Traversal of a Binary Tree using Recursion
  13. 13Inorder Traversal of a Binary Tree using Iteration
  14. 14Left View of a Binary Tree
  15. 15Right View of a Binary Tree
  16. 16Top View of a Binary Tree
  17. 17Bottom View of a Binary Tree
  18. 18Zigzag Traversal of a Binary Tree
  19. 19Check if a Binary Tree is Balanced
  20. 20Diagonal Traversal of a Binary Tree
  21. 21Boundary Traversal of a Binary Tree
  22. 22Construct a Binary Tree from a String with Bracket Representation
  23. 23Convert a Binary Tree into a Doubly Linked List
  24. 24Convert a Binary Tree into a Sum Tree
  25. 25Find Minimum Swaps Required to Convert a Binary Tree into a BST
  26. 26Check if a Binary Tree is a Sum Tree
  27. 27Check if All Leaf Nodes are at the Same Level in a Binary Tree
  28. 28Lowest Common Ancestor (LCA) in a Binary Tree
  29. 29Solve the Tree Isomorphism Problem
  30. 30Check if a Binary Tree Contains Duplicate Subtrees of Size 2 or More
  31. 31Check if Two Binary Trees are Mirror Images
  32. 32Calculate the Sum of Nodes on the Longest Path from Root to Leaf in a Binary Tree
  33. 33Print All Paths in a Binary Tree with a Given Sum
  34. 34Find the Distance Between Two Nodes in a Binary Tree
  35. 35Find the kth Ancestor of a Node in a Binary Tree
  36. 36Find All Duplicate Subtrees in a Binary Tree

GraphsGraphs46

  1. 1Breadth-First Search in Graphs
  2. 2Depth-First Search in Graphs
  3. 3Number of Provinces in an Undirected Graph
  4. 4Connected Components in a Matrix
  5. 5Rotten Oranges Problem - BFS in Matrix
  6. 6Flood Fill Algorithm - Graph Based
  7. 7Detect Cycle in an Undirected Graph using DFS
  8. 8Detect Cycle in an Undirected Graph using BFS
  9. 9Distance of Nearest Cell Having 1 - Grid BFS
  10. 10Surrounded Regions in Matrix using Graph Traversal
  11. 11Number of Enclaves in Grid
  12. 12Word Ladder - Shortest Transformation using Graph
  13. 13Word Ladder II - All Shortest Transformation Sequences
  14. 14Number of Distinct Islands using DFS
  15. 15Check if a Graph is Bipartite using DFS
  16. 16Topological Sort Using DFS
  17. 17Topological Sort using Kahn's Algorithm
  18. 18Cycle Detection in Directed Graph using BFS
  19. 19Course Schedule - Task Ordering with Prerequisites
  20. 20Course Schedule 2 - Task Ordering Using Topological Sort
  21. 21Find Eventual Safe States in a Directed Graph
  22. 22Alien Dictionary Character Order
  23. 23Shortest Path in Undirected Graph with Unit Distance
  24. 24Shortest Path in DAG using Topological Sort
  25. 25Dijkstra's Algorithm Using Set - Shortest Path in Graph
  26. 26Dijkstra’s Algorithm Using Priority Queue
  27. 27Shortest Distance in a Binary Maze using BFS
  28. 28Path With Minimum Effort in Grid using Graphs
  29. 29Cheapest Flights Within K Stops - Graph Problem
  30. 30Number of Ways to Reach Destination in Shortest Time - Graph Problem
  31. 31Minimum Multiplications to Reach End - Graph BFS
  32. 32Bellman-Ford Algorithm for Shortest Paths
  33. 33Floyd Warshall Algorithm for All-Pairs Shortest Path
  34. 34Find the City With the Fewest Reachable Neighbours
  35. 35Minimum Spanning Tree in Graphs
  36. 36Prim's Algorithm for Minimum Spanning Tree
  37. 37Disjoint Set (Union-Find) with Union by Rank and Path Compression
  38. 38Kruskal's Algorithm - Minimum Spanning Tree
  39. 39Minimum Operations to Make Network Connected
  40. 40Most Stones Removed with Same Row or Column
  41. 41Accounts Merge Problem using Disjoint Set Union
  42. 42Number of Islands II - Online Queries using DSU
  43. 43Making a Large Island Using DSU
  44. 44Bridges in Graph using Tarjan's Algorithm
  45. 45Articulation Points in Graphs
  46. 46Strongly Connected Components using Kosaraju's Algorithm

TriesTries1

Cycle Detection in Directed Graph
Using BFS (Kahn’s Algorithm)



Problem Statement

Cycle detection in a directed graph is a crucial problem in graph theory, especially for applications like scheduling, dependency resolution, and compiler design. A cycle exists when a node points back to itself through a path of directed edges.

This implementation uses Kahn’s Algorithm, which is a BFS-based approach relying on in-degree tracking of nodes.

If the graph can be topologically sorted (i.e., every node is visited exactly once), it does not contain a cycle. Otherwise, a cycle exists.

Examples

Graph (Adjacency List) Cycle Detected Description
{ 0: [1], 1: [2], 2: [3], 3: [] } No Linear graph with no back edges
{ 0: [1], 1: [2], 2: [0] } Yes Cycle exists: 0 → 1 → 2 → 0
{ 0: [1], 1: [2], 2: [], 3: [1] } No Disconnected graph with no cycle
{ 0: [1], 1: [2], 2: [3], 3: [1] } Yes Cycle exists: 1 → 2 → 3 → 1
{} No Empty graph with no nodes or edges

Solution

Understanding the Problem

In a directed graph, a cycle occurs when a node eventually points back to itself through a sequence of directed edges. To detect this, we use Kahn’s Algorithm, which is typically used for topological sorting but can also be used for cycle detection.

Step-by-Step Explanation

We start by calculating the in-degree (number of incoming edges) for every node. Nodes with zero in-degree are not dependent on any other node and can be processed first.

We use a queue to keep track of these zero in-degree nodes. As we process a node, we reduce the in-degree of its neighbors. If any of these neighbors reach zero in-degree, they are added to the queue.

We also keep a counter (visitedCount) to track how many nodes we have processed in this way.

Case 1: No Cycle Exists

If the graph has no cycles, eventually every node will be processed, and the visitedCount will equal the total number of nodes. This means we were able to complete a topological sort, indicating no cycles.

Case 2: Cycle Exists

If there is a cycle, some nodes will always have a non-zero in-degree, because they are dependent on each other. These nodes will never enter the queue, so visitedCount will be less than the total number of nodes. This tells us a cycle exists.

Example

Consider a graph with edges: 0 → 1, 1 → 2, 2 → 0. All nodes are part of a cycle. No node has zero in-degree, so the queue is initially empty. visitedCount stays 0, and we detect a cycle.

Now consider a graph with edges: 0 → 1, 1 → 2. This has no cycle. Nodes will be processed one by one (0, then 1, then 2), and visitedCount becomes 3 (equal to number of nodes). No cycle is detected.

Algorithm Steps

  1. Initialize an inDegree map for all nodes with value 0.
  2. Loop through the graph to compute in-degrees of all nodes.
  3. Create a queue and enqueue all nodes with in-degree 0.
  4. Initialize a visitedCount to 0.
  5. While the queue is not empty:
    1. Dequeue a node.
    2. Increment visitedCount.
    3. For each neighbor:
      • Decrement their in-degree by 1.
      • If in-degree becomes 0, enqueue the neighbor.
  6. After traversal, if visitedCount is less than total nodes, return true (cycle exists); else false.

Code

JavaScript
function hasCycle(graph) {
  const inDegree = {};
  const queue = [];
  const totalNodes = Object.keys(graph).length;
  let visitedCount = 0;

  // Initialize in-degrees
  for (const node in graph) {
    inDegree[node] = 0;
  }
  for (const node in graph) {
    for (const neighbor of graph[node]) {
      inDegree[neighbor] = (inDegree[neighbor] || 0) + 1;
    }
  }

  // Enqueue nodes with in-degree 0
  for (const node in inDegree) {
    if (inDegree[node] === 0) queue.push(node);
  }

  while (queue.length > 0) {
    const current = queue.shift();
    visitedCount++;
    for (const neighbor of graph[current] || []) {
      inDegree[neighbor]--;
      if (inDegree[neighbor] === 0) queue.push(neighbor);
    }
  }

  return visitedCount !== totalNodes;
}

const graph1 = { 0: [1], 1: [2], 2: [0] };
const graph2 = { 0: [1], 1: [2], 2: [] };

console.log("Cycle in graph1:", hasCycle(graph1)); // true
console.log("Cycle in graph2:", hasCycle(graph2)); // false

Time Complexity

CaseTime ComplexityExplanation
Best CaseO(V + E)Even in the best case, we must visit each node and each edge at least once to calculate in-degrees and simulate the process.
Average CaseO(V + E)Each node and its edges are processed exactly once while maintaining the in-degree and queue.
Worst CaseO(V + E)The algorithm still processes every node and edge regardless of the presence or absence of cycles.

Space Complexity

O(V)

Explanation: We use additional space for the in-degree map, queue, and visited counter—all of which depend on the number of nodes.



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