To determine if two strings are anagrams, we need to check if they contain the exact same characters with the exact same frequency, regardless of order or case. For beginners, think of it like this: can one string be rearranged to form the other?
Let’s Break Down the Possibilities
Case 1: Different lengths
If the strings have different lengths, they cannot be anagrams. For example, 'hello' and 'helloo' cannot be rearranged into each other—one has an extra character.
Case 2: Same letters, same frequency
This is the classic anagram case. 'listen' and 'silent' both have the letters l, i, s, t, e, n exactly once. So they are anagrams.
Case 3: Same letters, different frequency
If 's1' = 'aabbcc' and 's2' = 'abc', the letters may match but the count is different. Two 'a's in one string and only one in the other. So, not an anagram.
Case 4: Completely different letters
Obvious case—'abc' and 'xyz' share no characters at all, so they are not anagrams.
Case 5: Case sensitivity
We usually want to ignore case. So 'Listen' and 'Silent' should be considered anagrams. This means we convert both strings to lowercase before comparing.
Case 6: Empty strings
If both strings are empty, we consider them trivially anagrams—they contain the same (no) characters. But if only one is empty and the other is not, they are not anagrams.
What’s the Best Way to Solve This?
We compare the frequency of each character in both strings using a data structure like a map or dictionary. After converting both to lowercase, we count how many times each character appears in each string. If all characters and their frequencies match, they’re anagrams.
This solution is efficient and works in linear time relative to the length of the strings, since we only pass through each character a couple of times.