Yandex

Binary TreesBinary Trees36

  1. 1Preorder Traversal of a Binary Tree using Recursion
  2. 2Preorder Traversal of a Binary Tree using Iteration
  3. 3Postorder Traversal of a Binary Tree Using Recursion
  4. 4Postorder Traversal of a Binary Tree using Iteration
  5. 5Level Order Traversal of a Binary Tree using Recursion
  6. 6Level Order Traversal of a Binary Tree using Iteration
  7. 7Reverse Level Order Traversal of a Binary Tree using Iteration
  8. 8Reverse Level Order Traversal of a Binary Tree using Recursion
  9. 9Find Height of a Binary Tree
  10. 10Find Diameter of a Binary Tree
  11. 11Find Mirror of a Binary Tree - Todo
  12. 12Inorder Traversal of a Binary Tree using Recursion
  13. 13Inorder Traversal of a Binary Tree using Iteration
  14. 14Left View of a Binary Tree
  15. 15Right View of a Binary Tree
  16. 16Top View of a Binary Tree
  17. 17Bottom View of a Binary Tree
  18. 18Zigzag Traversal of a Binary Tree
  19. 19Check if a Binary Tree is Balanced
  20. 20Diagonal Traversal of a Binary Tree
  21. 21Boundary Traversal of a Binary Tree
  22. 22Construct a Binary Tree from a String with Bracket Representation
  23. 23Convert a Binary Tree into a Doubly Linked List
  24. 24Convert a Binary Tree into a Sum Tree
  25. 25Find Minimum Swaps Required to Convert a Binary Tree into a BST
  26. 26Check if a Binary Tree is a Sum Tree
  27. 27Check if All Leaf Nodes are at the Same Level in a Binary Tree
  28. 28Lowest Common Ancestor (LCA) in a Binary Tree
  29. 29Solve the Tree Isomorphism Problem
  30. 30Check if a Binary Tree Contains Duplicate Subtrees of Size 2 or More
  31. 31Check if Two Binary Trees are Mirror Images
  32. 32Calculate the Sum of Nodes on the Longest Path from Root to Leaf in a Binary Tree
  33. 33Print All Paths in a Binary Tree with a Given Sum
  34. 34Find the Distance Between Two Nodes in a Binary Tree
  35. 35Find the kth Ancestor of a Node in a Binary Tree
  36. 36Find All Duplicate Subtrees in a Binary Tree

GraphsGraphs46

  1. 1Breadth-First Search in Graphs
  2. 2Depth-First Search in Graphs
  3. 3Number of Provinces in an Undirected Graph
  4. 4Connected Components in a Matrix
  5. 5Rotten Oranges Problem - BFS in Matrix
  6. 6Flood Fill Algorithm - Graph Based
  7. 7Detect Cycle in an Undirected Graph using DFS
  8. 8Detect Cycle in an Undirected Graph using BFS
  9. 9Distance of Nearest Cell Having 1 - Grid BFS
  10. 10Surrounded Regions in Matrix using Graph Traversal
  11. 11Number of Enclaves in Grid
  12. 12Word Ladder - Shortest Transformation using Graph
  13. 13Word Ladder II - All Shortest Transformation Sequences
  14. 14Number of Distinct Islands using DFS
  15. 15Check if a Graph is Bipartite using DFS
  16. 16Topological Sort Using DFS
  17. 17Topological Sort using Kahn's Algorithm
  18. 18Cycle Detection in Directed Graph using BFS
  19. 19Course Schedule - Task Ordering with Prerequisites
  20. 20Course Schedule 2 - Task Ordering Using Topological Sort
  21. 21Find Eventual Safe States in a Directed Graph
  22. 22Alien Dictionary Character Order
  23. 23Shortest Path in Undirected Graph with Unit Distance
  24. 24Shortest Path in DAG using Topological Sort
  25. 25Dijkstra's Algorithm Using Set - Shortest Path in Graph
  26. 26Dijkstra’s Algorithm Using Priority Queue
  27. 27Shortest Distance in a Binary Maze using BFS
  28. 28Path With Minimum Effort in Grid using Graphs
  29. 29Cheapest Flights Within K Stops - Graph Problem
  30. 30Number of Ways to Reach Destination in Shortest Time - Graph Problem
  31. 31Minimum Multiplications to Reach End - Graph BFS
  32. 32Bellman-Ford Algorithm for Shortest Paths
  33. 33Floyd Warshall Algorithm for All-Pairs Shortest Path
  34. 34Find the City With the Fewest Reachable Neighbours
  35. 35Minimum Spanning Tree in Graphs
  36. 36Prim's Algorithm for Minimum Spanning Tree
  37. 37Disjoint Set (Union-Find) with Union by Rank and Path Compression
  38. 38Kruskal's Algorithm - Minimum Spanning Tree
  39. 39Minimum Operations to Make Network Connected
  40. 40Most Stones Removed with Same Row or Column
  41. 41Accounts Merge Problem using Disjoint Set Union
  42. 42Number of Islands II - Online Queries using DSU
  43. 43Making a Large Island Using DSU
  44. 44Bridges in Graph using Tarjan's Algorithm
  45. 45Articulation Points in Graphs
  46. 46Strongly Connected Components using Kosaraju's Algorithm

TriesTries1

Check if a Graph is Bipartite
Using Depth-First Search (DFS)



Problem Statement

Given an undirected graph represented as an adjacency list with V vertices (0-indexed), determine if the graph is bipartite.

A graph is bipartite if we can split the set of vertices into two groups such that no two adjacent vertices belong to the same group. This is equivalent to checking if the graph can be coloured using two colours without any two adjacent nodes having the same colour.

Examples

Adjacency List Is Bipartite? Description
{ 0: [1, 3], 1: [0, 2], 2: [1, 3], 3: [0, 2] } Yes Even cycle, can be coloured using two colours
{ 0: [1, 2], 1: [0, 2], 2: [0, 1] } No Triangle, odd cycle cannot be bipartite
{} Yes Empty graph is trivially bipartite
{ 0: [] } Yes Single isolated node
{ 0: [1], 1: [0], 2: [3], 3: [2] } Yes Two separate components, both bipartite

Solution

Understanding the Problem

A graph is bipartite if you can divide its set of vertices into two groups such that no two vertices within the same group are adjacent. In simple terms, adjacent vertices must always belong to opposite groups.

Using DFS to Check Bipartiteness

We use Depth-First Search (DFS) to try and color each node of the graph using two colors (say, 0 and 1). If any adjacent node has the same color, the graph is not bipartite.

Handling Different Scenarios

Case 1: Connected Graph

Start from any node and use DFS to color the graph. If you can color the entire graph without any two connected nodes having the same color, the graph is bipartite.

Case 2: Disconnected Graph

If the graph has multiple disconnected components, we need to perform DFS from each unvisited node. Each component must independently satisfy the bipartite condition.

Case 3: Presence of Odd-Length Cycle

Any graph containing an odd-length cycle cannot be bipartite. While coloring, you’ll find a point where two adjacent nodes need the same color—this is your cue the graph is not bipartite.

Case 4: Empty Graph

An empty graph (with zero edges) is trivially bipartite because there are no edges to violate the bipartite rule.

Conclusion

If all nodes (across all components) can be colored with two alternating colors using DFS without conflict, the graph is bipartite. Otherwise, it is not.

Algorithm Steps

  1. Create a color array of size V initialized with -1 (unvisited).
  2. Define a recursive dfs function that takes current node and currentColor.
  3. Color the node and for each of its neighbors:
    1. If neighbor is not coloured, call dfs with opposite colour.
    2. If already coloured and same as current node, return false.
  4. If DFS completes without conflicts, return true.
  5. Check each unvisited node to ensure disconnected components are handled.

Code

JavaScript
function isBipartiteDFS(adj, V) {
  const color = new Array(V).fill(-1);

  function dfs(node, c) {
    color[node] = c;

    for (const neighbor of adj[node] || []) {
      if (color[neighbor] === -1) {
        if (!dfs(neighbor, 1 - c)) return false;
      } else if (color[neighbor] === color[node]) {
        return false;
      }
    }
    return true;
  }

  for (let i = 0; i < V; i++) {
    if (color[i] === -1) {
      if (!dfs(i, 0)) return false;
    }
  }
  return true;
}

// Example usage
const graph1 = { 0: [1, 3], 1: [0, 2], 2: [1, 3], 3: [0, 2] };
console.log("Is graph1 bipartite?", isBipartiteDFS(graph1, 4)); // true

const graph2 = { 0: [1, 2], 1: [0, 2], 2: [0, 1] };
console.log("Is graph2 bipartite?", isBipartiteDFS(graph2, 3)); // false

Time Complexity

CaseTime ComplexityExplanation
Best CaseO(V + E)Even in the best case, we must traverse all vertices and their edges to ensure bipartite coloring without assumptions.
Average CaseO(V + E)Each vertex and edge is visited once during the DFS traversal.
Worst CaseO(V + E)In the worst case, the graph is fully connected and requires full traversal of all vertices and edges.

Space Complexity

O(V)

Explanation: We use a color array of size V and recursive call stack of maximum depth V in the worst case.



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